Platinum crystallize in a face-centred cubic crystal with a unite cell length a. the distance between nearest neighbours is:

Platinum crystallize in a face centered cube crystal with a unit cell length of 3.9231 Å . The density and atomic radius of platinum are respectively: [Atomic mass of Pt = 195]

Potassium crystallizes in body centered cubic lattice with a unit cell length a = 5.2 Å (A) what is the distance betweenn nearest neighbourss? (B) What is the distance between next nearest neighbour ? (C) How many nearest neighbours does each K atom have ? (D) How many next nearest neighbours does each K has ? (E) What is calculated density of crystalline K

An element crystallises in a face -centred cubic (fcc) unit cell with cell edge a. The distance between the centre of two nearest octahedral voids in the crystal lattice is ::

In face-centred cubic unit cell :

Xenon crystallizes in the face-centred cubic lattice and the edge of the unit cell is 620 pm. What is the nearest neighbour distance and what is the redius of xenon atom?

Ar crystallizes in an F.C.C. lattice . If the unit cell length is 5.311 A^(@) . find the distance between nearest neighbours.

In a face- centred cubic unit cell, the edge length is

Platinum crystallizes in fcc crystal with a unit cell length a . The atomic radius of platinum is therefore asqrt2//2 .