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Ice crystallizes in a hexagonal lattice....

Ice crystallizes in a hexagonal lattice. At the low temperature at which the structure was determined, the lattice constants were `a = 4.53 Å` and `c = 7.41 Å` (as shown in fig.) How many `H_(2)O` molecules are contained in a unit cell ? (Density of ice `= 0.92 gm//c c`)

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Ice crystallizes in a hexagonal lattice. At the low temperature at which the structure was determined, the lattice constants were a = 4.53 Å and c = 7.41 Å (as shown in fig). How mant H_(2)O molecules are contained in a unit cell ? (Density of ice = 0.92 gm/cc)

Ice crystallizes in hexagonal lattice. At the low temperature at which structure was determined, the lattice contents were were a=4.53Å and c=7.41Å . c=741Å . Calcuate the no. of H_(2)O molecules present in a unit cell. ( Density of ice =9.22g//cm)

Ice crystallizes in a hexagonal lattice. At ascertain low temperature, the lattice constants are a = 4.53 Å and c = 7.41 Å . The number of H_(2)O molecules contained in a unit cell ( d ~~ 0.92 g cm^(-3) at the given temperature) is

A_(2)B molecules (" molar mass " = 259.8 g//"ml") crystallises in a hexagonal lattice as shown in figure .The lattic constants were a=5 Å and b=8 Å . If denstiy of crystal is 5 g//cm^(3) then how many molecules are contained in given unit cell ? (" Use" N_(A) = 6xx10^(23))

A molecule A_(2)B (Mw = 166.4) occupies triclinic lattice with a = 5 Å, b = 8 Å , and c = 4 Å ,. If the density of AB_(2) is 5.2 g cm^(-3) , the number of molecules present in one unit cell is

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