Please help Sabu decode the jail lock. Chacha Choudhary gave Sabu a formula :
`f_(1) = ((x)/(z)xx y), f_(2) =((f)/(v) xxu), f_(3) = ((r)/(s)xx w)`
Sabu can open the lock if he finds the value of `3f_(1) +f_(2) +f_(3) =`key where:
Number of triangular faces in a truncated tetrahedron = x
Number of hexagonal faces in a truncated tetrahedron = x
Number of corners in a truncated tetrahedron = z Number of square faces in a truncated octahedron = t
Number of hexagonal faces in a truncated octahedron = u
Number of corners in a truncated octahedron = u
Number of triangular faces in a truchcated cube = w
Number of octangonal faces in a truncated cube = r Number of corners in a truncated cube = s What is the KEY ?