The potential enery of a charged parallel plate capacitor is `U_(0)`. If a slab of dielectric constant K is inserted between the plates, then the new potential energy will be

A charged parallel plate capacitor has a potential energy U. if a slab of dielectric constant k is inserted between the plates, then the new potential energy will be_

A parallel plate capacitor carries a harge Q. If a dielectric slab with dielectric constant K=2 is dipped between the plates, then

A parallel capacitor has capacitance 20muF . A potential difference of 220 V is applied across it. Calculate the charge on the plates and energy stored in the capacitor. If a dieletric slab of dielectric constant 5 is introduced between its plates, calculate the new value of potential difference and the energy stored.

A parallel capacitor of capacitance C is charged and disconnected from the battery. The energy stored in it is E . If a dielectric slab of dielectric constant 6 is inserted between the plates of the capacitor then energy and capacitance will become.

The plates of a parallel plate capacitor are charged to 100V. Then a 4mm thick dielectric slab is inserted between the plates and then to obtain the original potential difference , the distance between the system plates is increased by 2.00 mm. the dielectric constant of the slab is

A parallel - plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected . A slab of dielectric constant K is then inserted between the plate of the capacitor so as to fill the space between the plate .Find the work done on the system in the process of inserting the slab.

A parallel - plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected . A slab of dielectric constant K is then inserted between the plate of the capacitor so as to fill the space between the plate .Find the work done on the system in the process of inserting the slab.

A parallel - plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected . A slab of dielectric constant K is then inserted between the plate of the capacitor so as to fill the space between the plate .Find the work done on the system in the process of inserting the slab.