If x^3+6x^2+4x+k , is exactly divisible ...

If `x^3+6x^2+4x+k` , is exactly divisible by `(x+2)`, then the value of k is:

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x+2=0
x=-2
putting this value in our equation.
`f(x)=x^3+6x^2+4x+k=0`
`f(-2)=(-2)^3+6(-2)^2+4(-2)+k=0`
`=8+24-8+k=0`
`k=-8`.

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