[2x+ky=1],[5x-7y=5]

For the following system of equations determine the value of k for which the given system of equations has a unique solution: 2x+ky=1,quad 5x-7y=5

Find the value of k for which the following system of equation has no solution: 2x+ky=11,quad 5x-7y=5

For what value of k, the pair of equation 2x+ky=1,3x-5y=7 has a unique solution?

Find the value of k for which the following system of linear equations : 2x -ky = 1, 3x - 5y = 7 will have :- a unique solution .

If 2x+ky=3,5x-2y=3and3x-y=2 are concurrent then the value of k is -

If 2x+ky-10=0, 5x+2y-7=0 are parallel, then the value of k =

I : The 2x+ky-10=0, 5x+2y-7=0 are parallel then k = 4. II : If 2x+ky-10=0, 5x+2y-7=0 are perpendicular then k = 5.

For what value of k does the system of equation 3x+ky=11 and 5x-7y=6 has no solution?

Find k,if the following equations are consistent: ky=x+1,2x-3y+5=0,3x+2y+1=0