((m+n)/(7))^(3)(m-(n)/(7))

If (7m+2n)/(7m-2n)=5/(3) use properties of proportion to find (i) m:n (ii) (m^(2)+n^(2))/(m^(2)-n^(2))

((-21)/(2)m)/(2)=(7)/(2)n mn ne 0 {:("Quantity A","Quantity B"),(3m,-n):}

If (m+n)/(m-n)=7/3 then (m^2-n^2)/(m^2+n^2)=

Factorize the following polynomials 14m^(5)n^(4)p^(2)-42m^(7)n^(3)p^(7)-70m^(6)n^(4)p^(3)

For any two positive rational numbers m and n , a binary operation is defined by m+ n = (m+n)/(3) then (7)/(2) +(5)/(2) is equal to

4.(5m+5n)/(7m+7n)7*(x^(2)-9)/(x^(2)+6x+9)

(m+2)/(n+3)=(3)/(5) and (m+7)/(n+11)=(2)/(3) then solve m=?

If four different positive integers m,n,p and q satisfy the equation (7-m)(7-n)(7-p)(7-q)=4, then the sum(m+n+p+q) is equal to: