A proton has kinetic energy E = 100 keV which is equal to that of a photon. The wavelength of photon is `lamda_(2)` and that of proton is `lamda_(1)`. The ratio of `lamda_(2)//lamda_(1)` is proportional to

A proton has kinetic energy E = 100 keV which is equal to that of a photo is lambda_(1) . The ratio of k_(2) // lambda_(1) is proportional to

A proton with KE equal to that a photono (E = 100 keV). lambda_(1) is the wavelength of proton and lambda_(2) is the wavelength of photon. Then lambda_(1)/lambda)_(2) is proportional to:

Momentum of a photon of wavelength lamda is

The energy of a photon is E which is equal to the kinetic energy of a proton.If lambda1 be the de-Broglie wavelength of the proton and lambda2 be the wavelength of the photon,then the ratio (lambda_(1))/(lambda_(2)) is proportional to

The energy of a photon is equal to the kinetic energy of a proton. The energy of the photon is E. Let lambda_1 be the de-Broglie wavelength of the proton and lambda_2 be the wavelength of the photon. The ratio (lambda_1)/(lambda_2) is proportional to (a) E^0 (b) E^(1//2) (c ) E^(-1) (d) E^(-2)