[" If "A=[[sin theta,cos theta],[-cos theta,sin theta]]]

Simplify, costheta[[cos theta, sin theta],[-sin theta, cos theta]] + sin theta [[sin theta, -cos theta],[cos theta, sin theta]]

Simplify: cos theta[[cos theta , sin theta],[-sin theta , cos theta]]+sin theta[[sin theta, -cos theta],[cos theta ,sin theta]] .

sin4theta cos 2theta = cos5theta sin theta

If A = [(cos theta, sin theta),(-sin theta, cos theta)] and B = [(sin theta, - cos theta), (cos theta, sin theta)] , evaluate A cos theta + B sin theta .

Consider f(theta)=|[sin theta,cos theta,sin theta],[cos theta,sin theta,cos theta],[cos theta,sin theta,sin theta]| then A) f(theta)=0 has exactly 2 real solutions in [0,pi] B) f(theta)=0 has exactly 3 real solutions in [0,pi] C) Range of function (f(theta))/(1-sin2 theta) is [-sqrt(2),sqrt(2)] D) Range of function (f(theta))/(sin2 theta-1) is [-3,3]

Simplify cos theta[(cos theta,sin theta),(-sin theta,cos theta)]+sin theta[(sin theta,-cos theta),(cos theta,sin theta)]

Simplify : cos theta[(cos theta,sin theta),(-sin theta,cos theta)]=sin theta[(sin theta,-cos theta),(cos theta,sin theta)]