`8x^2-26x-7=0`

Find cos(alpha+beta) if tan(alpha/2) and tan (beta/2) are roots of the equiation 8x^2-26x+15=0

If tan(alpha/2) and tan(beta/2) are the roots of the equation 8x^2-26x+15=0 then cos(alpha+beta) is equal to

If tan""(alpha)/(2)andtan""(beta)/(2) are roots of the equation 8x^(2)-26x+15=0 then cos(alpha+beta) = …………

If tan((alpha)/(2)) and tan (( beta)/(2)) are the roots of the equation 8x^(2)-26x+15=0 then cos (alpha+ beta)=

If tan((alpha)/(2)) and (tan beta)/(2) are the roots of the equation 8x^(2)-26x+15=0 then the cos(alpha+beta) is equal to

If "tan"(alpha)/(2) and "tan"(beta)/(2) are the roots of the equation 8x^(2)-26x+15=0 , then find the value of "tan"((alpha+beta)/(2))

Solve the equation : 3x^(4)-16x^(3)+26x^(2)-16x+3=0

Find the equation whose roots are 3 times the roots of 6x^4 -7x^3 +8x^2 -7x +2=0