Five coins whose faces are marked 2, 3 a...

Five coins whose faces are marked 2, 3 are thrown. What is the probability of obtaining a total of 12?

Verified by Experts

Favorable case`->(5!)/(3!2!)=>(5*4*3*2)/(3*2*2)=10`
Total case`=2^5=32`
`P=10/32=5/16`.

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