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[" 1) 3/5"quad 2)5/3quad " 3) "4/5quad "...

[" 1) 3/5"quad 2)5/3quad " 3) "4/5quad " 4) "sqrt(2)],[" 18."4tan^(-1)(1)/(5)-tan^(-1)(1)/(70)+tan^(-1)(1)/(99)=],[" 1) "piquad " 2) "pi/2quad " 3) "pi/4quad " 4) "3 pi]

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4tan^(-1)((1)/(5))-tan^(-1)((1)/(70))+tan^(-1)((1)/(99))=pi/4

4tan^(- 1)(1/5)=tan^(- 1)(1/70)-tan^(- 1)(1/99)+pi/4

4tan^(- 1)(1/5)=tan^(- 1)(1/70)+tan^(- 1)(1/99)+pi/4

4tan^(-1)((1)/(5))=tan^(-1)((1)/(70))+tan^(-1)((1)/(99))+(pi )/(4)

tan^(-1)((3)/(n))+tan^(-1)((4)/(n))=(pi)/(2)

Show that 4 tan^-1 (1/5) - tan^-1 (1/70) + tan^-1 (1/99) = pi/4

tan^(-1)2x+tan^(-1)3x=(pi)/(4)

tan^(-1)(x/2)+tan^(-1)(x/3)=(pi)/(4)

tan[2tan^(-1)((1)/(5))+(pi)/(4)]

prove that , 4 tan ^(-1) ""(1)/(5) -tan ^(-1 )""(1)/(70) + tan ^(-1) ""(1)/(99) = (pi)/(4) .