C_(p)-C_(V)=R." This R is: "

For a gas C_(P)-C_(V)=R in a state P and C_(P)-C_(V)=1.10 R in a state Q, T_(P) and T_(Q) are the temperatures in two different states P and Q respectively. Then

Assertion: C_(p) can be less than C_(V) . Reason: C_(p)C_(V)=R is valid only for ideal gases.

Assertion: C_(p) can be less than C_(V) . Reason: C_(p)C_(V)=R is valid only for ideal gases.

In Mayer's relation: C_(P)-C_(V)=R 'R' stands for:

In Mayer's relation: C_(P)-C_(V)=R 'R' stands for:

Prove C_(p) - C_(v) = R

if R is the molar gas constant and gamma=C_(P)//C_(V), then C_(V) is equal to

If R is the molar gas constant and gamma=C_(P)//C_(V), then C_(p) is equal to

The value of C_(P) - C_(v) = 1.00 R for a gas in state A and C_(P) - C_(v) = 1.06 R in another state. If P_(A) and P_(B) denote the pressure and T_(A) and T_(B) denote the temperature in the two states, then