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(64)/(125)a^(3)-(96)/(25)a^(2)+(18)/(5)a...

(64)/(125)a^(3)-(96)/(25)a^(2)+(18)/(5)a-8

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Factorise (64)/(125)a^3-(96)/(25)a^2+(48)/(5)a-8

Factorize: (64)/(125)x^(3)-8-(96)/(25)x^(2)+(48)/(5)x

Factorize: (64)/(125)x^3-8-(96)/(25)x^2+(48)/5x\

(1) (4)/((216)^((2)/(3)))+(1)/((256)^((3)/(4)))+(2)/((243)^((1)/(5))) (ii) ((64)/(125))^((2)/(3))+((256)/(625))^((1)/(4))+((3)/(7))^(0) (iii) ((81)/(16))^((3)/(4))(((25)/(9))^((3)/(2))-:((5)/(2))^(-3)) (iv) ((25)^((5)/(2))times(729)^((1)/(3)))/((125)^((2)/(3))times(27)^((2)/(3))times8^((4)/(3)))

Factorise 1+(27)/(125)a^3+(9a)/(5)+(27a^2)/(25)

Evaluate : ((64)/( 125))^(-(2)/(3)) +(1)/(((256)/(625) ) ^((1)/(4)))+ ( sqrt(25))/(" ^(3) sqrt(64))

Find the value of (9^(3//2)-3xx5^(0)-[(1)/(81)]^(-1//2))/(((64)/(125))^(-2//3)+(1)/(((256)/(625))^(1//4))+((sqrt(25))/(root(3)(64)))) .

Prove that: ((64)/(125))^(-2/3)+1/(((256)/(625))^(1/4))+\ ((sqrt(25))/(root(3)64))=(65)/(16)

Prove that . (i) [8^(-(2)/(3)) xx 2^((1)/(2))xx 25^(-(5)/(4))] div[32^(-(2)/(5)) xx 125 ^(-(5)/(6)) ] = sqrt(2) (ii) ((64)/(125))^(-(2)/(3)) = (1)/(((256)/(625))^((1)/(4)))+ (sqrt(25))/(root3(64)) = (65)/(16) (iii) [7{(81)^((1)/(4)) +(256)^((1)/(4))}^((1)/(4))]^(4) = 16807 .

Evaluate : 5^(-4)xx(125)^((5)/(3))+(25)^(-(1)/(2))