x^(2)+5x-(a^(2)+a-6)=0[" CBSE "2015]

Solve x^(2)+5x-(a^(2)+a-6)=0 .

Solve x^(2)+5x-(a^(2)+a-6)=0 .

x^(2)-5x+6>0

Two non-integer roots of (x^(2) - 5x)^(2) - 7 (x^(2) - 5x) + 6 = 0 are

lim _( xto 2) ( x^(2) - 5x+ 6)/( x^(2) -4) ( ( 0 )/( 0 ) " form ")

The number of real roots of the equation (x^(2)+5x+6)^(2)+5(x^(2)+5x+6)+6-x=0 is

The two circles x^(2) + y^(2) -2x + 6y + 6 = 0 and x^(2) + y^(2) -5x + 6y + 15 = 0

Universal set, U={x|x^(5)-6x^(4)+11x^(3)-6x^(2)=0} A={x|x^(2)-5x+6=0} B={x|x^(2)-3x+2=0} What is (AnnB) ' equal to ?

The roots of 6x^(4) - 5x^(3) - 38x^(2) - 5x + 6 = 0 are