Find the diameter of the circle `2x^(2)+2y^(2)-6x-9=0`.

The length of the diameter of the circle x^(2)+y^(2)-6x-8y=0" is "

The equation of the diameter of the circle x^(2) + y^(2) - 6x + 2y = 0 which passes through origin is

The equation of the diameter of the circle 3(x^(2)+y^(2))-2x+6x-9-0 which is perpendicular to the line 2x+3y=12 is

If one of the diameters of the circle x^(2)+y^(2)-2x-6y+6=0 is a chord to the circle with center (2,1) ,then the radius of the circle is

If one of the diameters of the circle x^(2)+y^(2)-2x-6y+6=0 is a chord to the circle with centre (2,1), then the radius of circle is:

The equation of the diameter of the circle x^(2) + y^(2) -4x-6y +3 = 0 that is perpendicular 2x + 5y-6 = 0 is

Find the equation of the diameter of the circle x^(2) + y^(2) - 4x + 6y + 9 = 0 which passes through the point (1, -2).

The line x+3y=0 is a diameter of the circle x^(2)+y^(2)-6x+2y=0

Find the position of the circles x^(2)+y^(2)-2x-6y+9=0 and x^(2)+y^(2)+6x-2y+1=0 with respect to each other.r:

If one of the diameters of the curve x^(2)+y^(2)-4x-6y+9=0 is a chord of a circle with centre (1,1), the radius of this circle is