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In the ground state of hydrogen atom, it...

In the ground state of hydrogen atom, its Bohr radius is `5.3xx10^(-11)m`. The atom is excited such that the radius becomes `21.2xx10^(-11)m`. Find the value of principal quantum number and total energy of the atom in excited state.

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The radius of hydrogen atom in its ground state is 5.3 xx 10^(-11)m . After collision with an electron it is found to have a radius of 21.2 xx 10^(-11)m . What is the principle quantum number of n of the final state of the atom ?

The radius of hydrogen atom in its ground state is 5.3 xx 10^(-11)m . After collision with an electron it is found to have a radius of 21.2 xx 10^(-11)m . What is the principle quantum number of n of the final state of the atom ?

The radius of hydrogen atom in its ground state is 5.3 xx 10^(-11)m . After collision with an electron it is found to have a radius of 21.2 xx 10^(-11)m . What is the principle quantum number of n of the final state of the atom ?