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Silver crystallises in a face-centred cu...

Silver crystallises in a face-centred cubic structure with unit cells having an edge length of 407pm. What is the radius of a silver atom in nm unit?

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In case of a face-centred cubic unit cell, the relation between the edge length (a) of the unit cell and the radius ( r) of its particle is, `a=rxx2sqrt2`
Putting a = 407pm = `407xx10^(-3)nm` into the above relation gives `r=a/(2sqrt2)=(407xx10^(-3))/(2sqrt(2))nm=0.1438nm`
Therefore, the radius of a silver atom = 0.1438 nm.
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