Home
Class 12
CHEMISTRY
Sodium crystallises in a body-centred cu...

Sodium crystallises in a body-centred cubic lattice with unit cells of edge length 4.29Å. Calculate the radius of a sodium atom and the distance between the nearest neighbours in the lattice.

Text Solution

Verified by Experts

The distance (d) between the nearest neighbours in a body-centred cubic unit cell in terms of edge length (a) of the cell and radius ( r) of its particle is, d = 2r = 0.866`xx`a.
As a = 4.29Å, 2r = 0.866`xx`a = 0.866`xx`4.29Å
or, r = 1.857Å
Therefore, the radius of a sodium atom is 1.857Å, and the distance between the nearest neighbours = 2r = 2`xx`1.857Å
= 3.714Å
Promotional Banner

Topper's Solved these Questions

  • SOLID STATE

    CHHAYA PUBLICATION|Exercise WARM UP EXERCISE|70 Videos

  • SOLID STATE

    CHHAYA PUBLICATION|Exercise VERY SHORT ANSWER TYPE|60 Videos

  • PREVIOUS YEARS QUESTION PAPER 2019

    CHHAYA PUBLICATION|Exercise WBCHSE 2019 PART-B|19 Videos

  • SOME p-BLOCK ELEMENTS

    CHHAYA PUBLICATION|Exercise PRACTIVE SET 11|15 Videos

Similar Questions

Explore conceptually related problems

Sodium metal crystallises in a body-centreed cubic lattice with a unit cell edge of 4.29Å. The radius of sodium atom is approximately-

Sodium metal crystllizes in a body centred cubic lattice with a unit cell edge of 4.56Å . The radius of sodium atom is approximately

Sodium metal crystallises in body centred cubic lattic with cell edge 5.20Å .What is the radius of sodium atom ?

Sodium crystallises in a body-centred cubic unit cell. (bcc) with edge length 4.29Å . What is the radius of the sodium atom ? What is the length of the body-diagonal of the unit cell?

Silver crystallises in a face-centred cubic structure with unit cells having an edge length of 407pm. What is the radius of a silver atom in nm unit?

NH_(4)Cl crystallises in a body centred cubic lattice with a unit cell distance of 387 pm. Calculate (a) the distance between the oppositely charged ions in the lattice. (b) the radius of NH_(4)^(+) ion if that of Cl^(-) ion is 181 pm.

(i) Which type of semiconductor is sillicon having arsenic as impurity? (ii) An elements (density = 7.2g*cm^(-3) ) crystallises in a body-centred cubic structure having its cell edge length 2.88Å. Calculate the number of atoms and the number of unit cells present in 156g of the element.

A metal crystallizes with a body-centred cubic lattice. The length of the unit cell edge is found to be 265 pm. Calculate the atomic radius.

An element crystallises in a body-centred cubic structure. The atomic radius of the element is 190pm. Calculate: (1) the distance between two nearest neighbours (2) the body diagonal and the edge length of the unit cell.

A compound AB crystallises in the b.c.c lattice with unit cell edge length of 390 pm. Calculate (a) the distance between the oppsitely charged ions in the lattice. (b) the radius of A^(+) ion if radius of B^(-) ion is 175 pm.