Classify the following substances as molecular, covalent, or ionic crystalline solids.
Boron nitride, ice, solid `CHCl_(3)`, silicon carbide, `Cacl_(2)`, silicon, LiI, Solid `P_(4)`, solid Ar, zinc sulphide.

Classify the following crystalline solids as molecular ionic, covalent and metallic solids: CaCl_(2) , Si, Ag, Glucose, Hg, HCl, BN, KOH

Classify the following solids based on the nature of intermolecular forces operating in them: Potassium sulphate, tin, benzene, urea, ammonia, water, zinc sulphide, graphite, rubidium, argon, silicon carbide.

Classify each of the following solids as ionic, metallic, molecular, network (covalent) or amorphous. (i) Tetraphosphorous decoxide (P_(4)O_(10)) (ii) Ammonium phosphate, (NH_(4))_(3)PO_(4) (iii) SiC (iv) I_(2) (v) P_(4) (vi) Plastic (vii) Graphite (viii) Brass (ix) Rb (x) LiBr (xi) Si

Classify the following solids in different categories based on the nature of intermolecular forces operating in them: ltbr. Potassium sulphate, tin, benzene, urea, ammonia, water, zinc sulphide,graphite, rubidium , argon, silicon carbide.

A solid substance 'A' is very hard and electrical insulator both in the solid state as well as in molten state. It has also very high melting point. Is the solid metal like silver or network solid like silicon carbide (SiC) ?

SnCl_2 is an ionic solid while SnCl_4 is a covalent liquid at room temperature - Explain.

Quantum mechanical calcuations show that mathematical mixing of certain combinaaation of orbitals in a given atom forms hybrid orbitals. The spatial orientations of these new orbitals lead to more stable bonds and are consistent with the observed molecular shapes . The process of orbital mixing is called hybridization and the new atomic orbitals are called hybrid orbitals.- Conditions (i) The no. of hybrid orbitals equal the number of atomic orbitalsmixed. (ii)The type of hybrid orbitals obtained varies with the type of atomic orbitals mixed. Rules to determine hybrid orbitals. Method i:Count no .of atoms directiy attached to central atom + lone pairs+single electrons. Method II: Count sigma - bonds+co-ordinate bonds+ lone pair+single electrons. If the number comes one to be 2 implies sp 5 implies sp^3d/dsp^3 3 implies sp^2 6 implies sp^3d^2/d^2sp^3 4 implies sp^3/dsp^2 7 implies sp^3d^3 Answer the following questions based on above passage : Phosphorous pentachloride in gaseous state exists as a momomer. In solid state, it exists as PCl_5^+. PCl_6^- ions. The hybrid state of P atom in PCl_5 is sp^3d . The hybrid state of P atoms in PCl_4^+ and PCl_6^- will be respectively

Explain with reason: SnCl_2 is a solid ionic compound whereas SnCl_4 is a covalent liquid.

Classify as open, closed or isolated system: (1) A cup of coffee placed on a table (2) Water in a beaker is boiled by heating (3) Lead nitrate is heated in a test tube (4) Solid NH_(4)Cl is heated in a closed vessel (5) Substances present in a soda-water bottle (6) Mercury enclosed in the thermometer.