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Iron has a body-centred cubic unit cell ...

Iron has a body-centred cubic unit cell dimension of 286.65pm. The density of iron is `7.874g*cm^(-3)`. Use the information to calculate Avogadro's number [Atomic mass of Fe = 55.845u]

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Given, a = 286.65pm = `286.65xx10^(-10)cm`
`rho=7.87g*cm^(-3),M=56g*mol^(-1)`
`thereforerho=(ZxxM)/(a^(3)xxN_(A))or,N_(A)=(ZxxM)/(a^(3)xxrho)`
or, `N_(A)=(2xx55.845)/((286.65xx10^(-10))^(3)xx7.874)`
`" "[becauseZ=2" for bcc crystal"]`
or, `N_(A)=6.022xx10^(23)`
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