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Silver crystallises in fcc lattice. If e...

Silver crystallises in fcc lattice. If edge length of the unit cell is `4.077xx10^(-8)`cm, then calculate the radius of silver atom.

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To calculate the radius ( r) of an atom of a fcc latice, we use the formula, `r=a/(2sqrt2)`(a = edge length of unit cell)
Given: `a=4.077xx10^(-8)cm`
`thereforer=(4.077xx10^(-8))/(2sqrt2)cm=1.441xx10^(-8)cm`
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