Copper crystallises into a fcc lattice with edge length `3.61xx10^(-8)cm`. Show that the calculated density is in agreement with its measured value of `8.96g*cm^(-3)`.

Explanation

We know, `rho=(ZxxM)/(Nxxa^(3))`
Given: a = `3.61xx10^(-8)cm`
For fcc lattice Z = 4 and fcc copper M = `63.5g*mol^(-1)`
`therefore" "rho=(4xx63.5)/(6.022xx10^(23)xx(3.61xx10^(-8))^(3))=8.96g*cm^(-3)`
Therefore, the calculated density `(8.96g*cm^(-3))` is in agreement with its measured value `(8.96g*cm^(-3))`.