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A metal (atomic mass = 63.5) forms cubic...

A metal (atomic mass = 63.5) forms cubic crystal. Its density is `8.92xx10^(3)kg*m^(-3)`. Edge length of the unit cell is 0.362 nm. How many atoms are present in the unit cell?

Text Solution

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`Z=(rhoxxa^(3)xxN)/M,rho=8.92xx10^(3)kg*m^(-3)=8.92g*cm^(-3)`
`a=0.362nm=0.362xx10^(-7)cm`
`thereforeZ=(8.92xx(0.362xx10^(-7))^(3)xx6.022xx10^(23))/63.5=4`
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