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The density of lead is 11.35g*cm^(-3) an...

The density of lead is `11.35g*cm^(-3)` and the metal crystallises with fcc unit cell. Estimate the radius of lead atom. [Given: Atomic mass of lead = 207`g*mol^(-1), N_(A)=6.022xx10^(23)`]

Text Solution

Verified by Experts

`rho=(ZxxM)/(Nxxa^(3))or,a^(3)=(ZxxM)/(Nxxrho)=(4xx207)/(6.022xx10^(23)xx11.35)`
`=1.212xx10^(-22)cm^(3)`
`thereforea=4.947xx10^(-8)cm`
The radius of lead atom = `a/(2sqrt2)=(4.947xx10^(-8))/(2sqrt2)`
`=1.749xx10^(-8)cm`
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