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Compare the radii of K^(+) and Cl^(-) io...

Compare the radii of `K^(+) and Cl^(-)` ions (each contain the same number of electron).

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The nucleic of the isoelectronic ions `K^(+) and Cl^(-)` contain 19 and 17 protons respectively. So the magnitude of nuclear attractive force acting on the electrons of `K^(+)` ion is greater than that on the electrons of `Cl^(-)` ion. Consequently, the radius of `K^(+)` ion is smaller than that of `Cl^(-)` ion.
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CHHAYA PUBLICATION-CLASSIFICATION OF ELEMENTS & PERIODICITY IN PROPERTIES-QUESTION-ANSWER ZONE FOR BOARD EXAMINATION
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