Is there any change in the hybridisation of B and N atoms as a result of the following reaction?
`BF_(3)+NH_(3) to F_(3)B*NH_(3)`

Explanation

N in `overset(..)(N)H_(3)` is the donor and B and `BF_(3)` is the acceptor. The hybrid state of B in `BF_(3)` is `sp^(2)` and that of N in `NH_(3)` is `sp^(3)`. In the compound `F_(3)B*NH_(3)`, both N and B atoms are surrounded by 4 bond pairs. Thus both have a hybrid state of `sp^(3)`. hence, during combination, the hybrid state of B changes from `sp^(2)` to `sp^(3)` but that of N remains the same.