Which statements are correct for the peroxide ion-

Options

A. it has five completely filled anti-bonding molecular orbitals
B. it is diamagnetic
C. it has bond order one
D. It is isoelectronic with neon

Answer

A

Explanation

MO electronic configuration of `O_(2)^(2-)` (peroxide ion):
`(sigma_(1s))^(2)(sigma_(1s)^(**))^(2)(sigma_(2s))^(2)(sigma_(2s)^(**))^(2)(sigma_(2p_(z)))^(2)`
`(pi_(2px))^(2)(pi_(2py))^(2)(pi_(2p_(x))^(**))^(2)(pi_(2p_(y))^(**))^(2)`
bond order`=(N_(b)-N_(a))/(2)=(10-8)/(2)=1`
Thus, there is no unpared electron present for which it becomes diamagnetic. its total no. of electrons=18 (same as that of Ne).