Considering the state of hybridisation of C-atoms, find out the molecule among the following which is linear-

Options

A. `CH_(3)-CH_(2)-CH_(3)-CH_(3)`
B. `CH_(3)-CH=CH-CH_(3)`
C. `CH_(3)-C-=C-CH_(3)`
D. `CH_(2)=CH-CH_(2)-C-=CH`

Answer

C

Explanation

In case of `sp^(3),sp^(2)` and sp hybridised carbons, bond angle is `109^(@)28'`: `120^(@)` and `180^(@)` respectively. So, only `CH_(3)-underset(sp)underset(uarr)(C)-=underset(sp)underset(uarr)(C)-CH_(3)` is linear (excluding H-atoms).