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At constant pressure, the temperature of...

At constant pressure, the temperature of a difinite amount of a gas is increased from `0^(@)C` to `t^(@)C`. As a result, the volume of the gas is increased by a factor of three. Calculate the value of t.

Text Solution

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We know, `V_(1)//V_(2)=T_(1)//T_(2)`
Given, `T_(1)=273,T_(2)=(273+t)K and V_(2)=3V_(1)`
(where `V_(1)` is the volume of the gas at `0^(@)C`)
`therefore (V_(1))/(3V_(1))=(273)/(273+t) or , 273+t=819" "therefore t=546^(@)K`.
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