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At a given temperature annd pressure, th...

At a given temperature annd pressure, the volume of 10 g of He gas is 61.6 L. how much of He gas has to be taken out at the same temperature and pressure to reduce its volume to 25 L?

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10 G `He=(10)/(4)=2.5" mol He"` [`because`Atomic mass of He=molarr mass of He (monatomic gas)=4`g*mol^(-1)`]
We know at constant temperature and pressure, `(V_(1))/(V_(2))=(n_(1))/(n_(2))`
Given, `V_(1)=61.6L,V_(2)=25L,n_(1)=2.5 and n_(2)=?`
`therefore n_(2)=n_(1)xx(V_(2))/(V_(1))=2.5xx(25)/(61.6)=1.015`mol
1.015 mol `He=4xx1.015=4.06`g He
`therefore`The volume of the gas will be 25 L if (10-4.06)=5.94g of He gas is taken out.
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