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Determine the relative rates of diffusio...

Determine the relative rates of diffusion of `""^(235)UF_(6)` and `""^(238)UF_(6)` gases?

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Molecular weight of `""^(235)UF_(6)=235+6xx19=349 and` molecular weight of `""^(238)UF_(6)=238+6xx19=352`
At a given temperature and pressure if `r_(1) and r_(2)` be the rates of diffusion of `""^(235)UF_(6) and ""^(238)UF_(6) ` respectively, then according to Graham's law,
`(r_(1))/(r_(2))=sqrt((M_(2))/(M_(1)))=sqrt((352)/(349))=1.0043" "therefore r_(1)=1.0043xxr_(2)`
`therefore`The rate of diffusion of `""^(235)UF_(6)` is 1.0043 times that of `""^(238)UF_(6)`.
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