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Determine the total kinetic energy of th...

Determine the total kinetic energy of the molecule of 1 g `CO_(2)` at `27^(@)C` in the units of erg and calorie. Assume the ideal behaviour of the gas.

Text Solution

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1 g `CO_(2)=(1)/(44)=2.27xx10^(-2)molCO_(2) and T=(273+27)K=300K`
total kinetic energy of molecules in 1 mol of an ideal gas `=(3)/(2)RT`. Therefore, total kinetic energy of the molecules of `2.27xx10^(-3)molCO_(2)` gas `=2.27xx10^(-2)xx(3)/(2)RT`
`=2.27xx10^(-2)xx(3)/(2)xx8.314xx10^(7)xx300`
`=8.5xx10^(8)erg=20.31 cal" "[because 1 cal=4.18xx10^(7)erg]`.
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