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Ratio of masses of oxygen & nitrogen in ...

Ratio of masses of oxygen & nitrogen in a gaseous mixture is 1:4 ratio of number of their molecules is-

A

`3:16`

B

`1:4`

C

`7:32`

D

`1:8`

Text Solution

Verified by Experts

The correct Answer is:
C
`(w_(O_(2)))/(w_(N_(2)))=(1)/(4) or, (n_(O_(2))xxM_(O_(2)))/(n_(N_(2))xxM_(N_(2)))=(1)/(4)` (n=number of moles)
or, `(n_(O_(2)))/(n_(N_(2)))=(1)/(4)xx(28)/(32)=(7)/(32)`
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