50 mL of each gas A and B takes 150s and 200s respectively for effusing through a pinhole under similar conditions. If molar mass of gas B is 36, molar rmass of gas A-

Options

A. 20.25
B. 64
C. 96
D. 128

Answer

A

Explanation

`(r_(A))/(r_(B))=sqrt((M_(B))/(M_(A))) or, (V_(A))/(t_(A))xx(t_(B))/(V_(B))=sqrt((M_(B))/(M_(A)))`
or, `(50)/(150)xx(200)/(50)=sqrt((36)/(M_(A))) or, (4)/(3)=sqrt((36)/(M_(A))) or, (16)/(9)=(36)/(M_(A))`
gt `therefore M_(A)=(36xx9)/(16)=20.25`