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In van der waals equation at temperature...

In van der waals equation at temperature 300k, if a=1.4 `atm*L^(-2)*mol^(-2),V=100mL,n=1` mole, then what is the pressure of the gas-

A

42 atm

B

210 atm

C

500 atm

D

106 atm

Text Solution

Verified by Experts

The correct Answer is:
D
At moderate pressure van der waals equation is given
as : `(P+(an^(2))/(V^(2)))(V)=nRT`
`(P+(1.4)/((0.1)^(2)))(0.1)=1xx0.082xx300`
or, `(P+140)xx0.1=24.6 or, 0.1P+14=24.6`
or, 0.1P=10.6 or, P=106 atm.
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