At 298 K the resistance of a 0.1M KCl solution is found to be 39.0ohm. If the conductivity (k) of this solution is 1.29`xx10^(-2)ohm^(-1)cm^(-1)` at 298K, what is cell contant

At 298 K the resistance of a 0.1M KCl solution is found to be 39.0ohm. If the conductivity (k) of this solution is 1.29 xx10^(-2)ohm^(-1)cm^(-1) at 298K, what is cell constant

The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500 ohm. What is the cell constant and molar conducti vity of 0.001 M KCI solution, if the conductivity of this solution is 0.146xx10^(-3)"ohm"^(-1)cm^(-1) at 298 K?

If conductivity of 0.1 mol/dm^3 solution of KCl is 1.3 * 10^(-2) S cm^(-1) at 298 K then its molar conductivity will be

At 298K the resistance of a 0.5N NaOH solution is 35.0 ohm. The cell constant is 0.503 cm^(-1) the electrical conductivity of the solution is

At 298K the resistance of a 0.5N NaOH solution is 35.0 ohm. The cell constant is 0.503 cm^(-1) the electrical conductivity of the solution is

If conductivity of 0.1 mol / dm^3 solution of KCl is 1.3 * 10^(-2) S cm^(-1) at 298 K then its molar conductivity will be

At 298K the electrolytic conductivity of a 0.2 M KCl solution is 2.5xx10^(-2) ohm^(-1)cm^(-1) compute its molar c onductivity.

Resistance of a 0.1 M KCl solution in a conductance cell is 300 ohm and specific conductance of "0.1 M KCl" is 1.33xx10^(-2)" ohm"^(-1)"cm"^(-1) . The resistance of 0.1 M NaCl solution in the same cell is 400 ohm. The equivalent conductance of the 0.1 M NaCl solution ("in ohm"^(-1)"cm"^(2)"/gmeq.") is

At 25^(@)C , the specific conductance and the resistance of a 1N solution of KCl in a conductivity cell are found to be 2.765xx10^(-3)" ohm"^(-1)."cm"^(-1) and 400 ohm respectively. The cell constant of the cell is -