A bar magnet of magnetic moment `200 A-m^(2)` is suspended in a magnetic field of intensity `0.25 N//A-m`. The couple required to deflect it through `30^(@)` is

A bar magnet has a magnetic moment of 200 A.m^(2) . The magnet is suspended in a magnetic field of 0.30NA^(-1)m^(-1) . The torque required to rotate the magnet from its equilibrium position through an angle of 30^(@) , will be

A bar magnet has a magnetic moment of 200 A m? The magnet is suspended in a magnetic field of 0.30 "N A"^(-1)" m"^(-1) . The torque required to rotate the magnet from its equilibrium position through an angle of 30^(@) , will be

A bar magnet has a magnetic moment of 200 A m? The magnet is suspended in a magnetic field of 0.30 "N A"^(-1)" m"^(-1) . The torque required to rotate the magnet from its equilibrium position through an angle of 30^(@) , will be

The magnetic moment of a magnet is 0.25 A-m^(2) . It is suspended in a magnetic field of intesity 2 xx 10^(-5) T . The couple acting on it when deflected by 30^(@) from the magnetic fields is .

The magnetic moment of a magnet is 0.25 A-m^(2) . It is suspended in a magnetic field of intesity 2 xx 10^(-5) T . The couple acting on it when deflected by 30^(@) from the magnetic fields is .

A bar magnet lies in a magnetic field of intensity 0.5 xx 10^(-4) tesla. The torque required to deflect it through 30^(@) is 2.5 xx 10^(-5)N m . Calculate the magnetic moment of the magnet.

A magnet of magnetic moment M is freely suspended in a constant uniform magnetic field of intensity H. Calculate work done in deflecting the magnet through an angle theta from the direction of H.