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If a triangle and a parallelogram are on the same base and between the same parallels, then prove that the area of the triangle is equal to half the area of the parallelogram.

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If a triangle and a parallelogram lie on the same base and between the same parallels, then prove that the area of the triangle is equal to half of the area of parallelogram.

Assertion : If area of Delta ABD is equal to 24 cm^(2) then a rea of p arallelogram ABCD is 24 cm^(2) Reason : If a triangle and a parallelogram are on the same base and between same parallels, then area of the triangle is equ al to h alf of the parallelogram.

If a triangle and a parallelogram are on the same base and between the same parallels lines, then the area of the triangle is equal to half that of the parallelogram. GIVEN : A triangle ABC and ||^(gm)BCDE on the same base BC and between the same parallels BC and AD . TO PROVE : ar (triangle ABC) =1/2 ar (||^(gm)BCDE) CONSTRUCTION : Draw AL _|_ BC and DM _|_ BC, produced at M.

In a triangle and a parallelogram are on the same base and between the same parallel; the area of the triangle is equal to half of the parallelogram.

If a triangle and a parallelogram are on the same base and between same parallels, then the ratio of the area of the triangle to the area of parallelogram is

If a triangle and a parallelogram are on the same base and between same parallels, then the ratio of the area of the triangle to the area of parallelogram is

If a triangle and a parallelogram are on the same base and between same parallels, then the ratio of the area of the triangle to the area of parallelogram is

If a triangle and a parallelogram are on the same base and between the same parallels, the area of the triangle is equal to half of the parallelogram. GIVEN : A ABC and ||^(gm)BCDE on the same base BC and between the same parallels BC and AD. TO PROVE : ar(ABC=1/2 ar(||^(gm)BCDE) CONSTRUCTION : Draw AL _|_ BC and DM _|_ bc, metting BC produced in M.

Parallelograms on the same base and between the same parallel are equal in area.