The vectors from origin to the points A and B are `vecA=3hati-6hatj+2hatk` and `vecB=2hati+hatj+2hatk` respectively. The are of triangle `OAB` be

The vectors from origin to the points A and B are vecA=3hati-6hatj+2hatk and vecB=2hati+hatj+2hatk respectively. The area of triangle OAB be

The vectors from origin to the points A and B are veca=2hati-3hatj+2hatk and vecb=2hati+3hatj+hatk , respectively then the area of triagnle OAB is

The vectors for origin to the points A and B are A=3hati-6hatj+2hatk and B=2hati+hatj-2hatk , respectively. The area of the DeltaOAB is

If veca=3hati-hatj+2hatk and vecb=2hati+3hatj+3hatk then veca.vecb is equal to :

Find the projection of the vector veca=2hati+3hatj+2hatk and vecb=hati-hatj+hatk

If veca=2hati+hatj+4hatk and vecb=3hati-2hatj+hatk then veca.vecb=

If vecA=3hati+hatj+2hatk and vecB=2hati-2hatj+4hatk , then value of |vecA+vecB| will be

Find vecB xx vecA if vecA = 3hati - 2hatj + 6hatk and vecB = hati - hatj + hatk .

If veca=3hati+hatj-4hatk and vecb=6hati+5hatj-2hatk find |veca Xvecb|