A solution containing 0.319 g of complex `CrCl_(3).6H_(2)O` was passed through cation exchanger and the solution given out was neutralised by 28.5 ml of 0.125 m NaOH. The correct formula of the complex will be: [ molecular weight of complex =266.5]

Options

A. `[CrCl(H_(2)O)_(5)]Cl_(2).H_(2)O`
B. `[CrCl(H_(2)O)_(6)]Cl_(3)`
C. `[CrCl_(2)(H_(2)O)_(4)]Cl.2H_(2)O`
D. all are correct

Answer

B

Explanation

`n_(CrCl_(3).6H_(2)O)=0.319/266.5`
m mol of NaOH=3.5625
`3Cl^(-)harr3OH^(-)rArr1.97xx3=3.5625`
`rArr [Cr(H_(2)O)6]Cl_(3)`