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Which change in [Mn(CN)(6)]^(4-) results...

Which change in `[Mn(CN)_(6)]^(4-)` results in symmetrical ditribution of electrons in non-degenerate d- orbitals of metal ion ?
`(P) [Mn(CN)_(6)]^(4-)underset(byO_(2))overset("oxidation")to [Mn(CN)_(6)]^(3-)`
`(Q) [Mn(CN)_(6)]^(4-)underset(by Zn)overset("reduction")to [Mn(CN)_(6)]^(5-)`

A

P only

B

Q only

C

P and Q both

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
`[overset(+2)Mn(CN)_(6)]^(5-) implies d^(5), t_(2g)^(2, 2, 2)e_(g)^(0, 0)`
`[overset(+1)Mn(CN)_(6)]^(5-) implies d^(6), t_(2g)^(2, 1, 1)e_(g)^(1, 1)`
[Due to low O.S. of `Mn(+1) Delta_(0) lt P`, hence, pairing does not occur.]
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