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On treatment of [Pt(NH(3))(4)]^(2+) with...

On treatment of `[Pt(NH_(3))_(4)]^(2+)` with concentrated HCI, two compounds (P) and (Q) having the same formula, `[Pt(NH_(3))_(2)CL_(2)]` are obtained, (P) can be converted into (Q) by boiling with dilute HCI. A soution of (P) reacts with oxalic acid to form `[Pt(NH_(3))_(2)(C_(2)O_(4))]` whereas (Q) does not react. Point out the correct statement of the following :

A

(P) cis, (Q) trans, both tetrahedral

B

(P) cis, (Q) trans, both square planar

C

(P) trains, (Q) cis, both tetrahedral

D

(P) trans, (Q) cis, both square planar

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The correct Answer is:
B

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When [Ni(NH_(3))_(4)]^(2+) is treated with conc HCI two compounds having the formula Ni(NH_(3))CI_(2) (designated as I and II are formed) I can be converted into II ny boiling in dil HCI A solution of I reacts with oxalic acid to form Ni(NH_(3))_(2)(C_(2)O_(4)) II does not react with oxalic acid Deduce the configuration Of I and II and the geometry of Ni (II) complexes .

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