Which of the following isomers of `[M(NH_(3))_(2)Cl_(2)]` would react with silver oxalate `(Ag_(2)C_(2)O_(4))` ?

Options

A.
B.
C. Both (a) and (b)
D. None of these

Explanation

To determine which isomer of the coordination compound \([M(NH_3)_2Cl_2]\) would react with silver oxalate \((Ag_2C_2O_4)\), we need to analyze the isomers and their potential interactions with the bidentate ligand (oxalate).

### Step-by-Step Solution:

1. **Identify the Isomers**:
The compound \([M(NH_3)_2Cl_2]\) can exist in two geometric isomers:
- **Cis isomer**: where the two ammonia ligands are adjacent to each other.
- **Trans isomer**: where the two ammonia ligands are opposite each other.

2. **Understand the Ligand Types**:
- Ammonia \((NH_3)\) is a monodentate ligand, meaning it can coordinate to the metal at only one site.
- Oxalate \((C_2O_4^{2-})\) is a bidentate ligand, meaning it can coordinate to the metal at two sites.

3. **Reaction with Bidentate Ligands**:
- For a bidentate ligand like oxalate to coordinate with the metal center, there must be two available coordination sites that are adjacent to each other.
- In the case of the cis isomer, the two ammonia ligands are adjacent, allowing the oxalate to effectively coordinate with the metal center.

4. **Conclusion**:
- The **cis isomer** of \([M(NH_3)_2Cl_2]\) will react with silver oxalate \((Ag_2C_2O_4)\) because it has the necessary adjacent coordination sites for the bidentate ligand to bind.
- The **trans isomer** will not react because the two ammonia ligands are positioned opposite each other, leaving no adjacent sites for the oxalate to bind.

### Final Answer:
The **cis isomer** of \([M(NH_3)_2Cl_2]\) would react with silver oxalate \((Ag_2C_2O_4)\).

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