Select the complex which show both structural and stereo isomerism :

Options

A. `[Pt(NH_(3))_(4)Cl_(2)]Cl_(2)`
B. `[Pt(NH_(3))_(5)Cl]Br_(3)`
C. `[Pt(en)_(2)Cl_(2)]Br_(2)`
D. `[Pt(NH_(3))_(2)(Cl)(Br)]`

Explanation

To solve the question of selecting the complex that shows both structural and stereo isomerism, we will follow these steps:

### Step 1: Understand the Types of Isomerism
- **Structural Isomerism**: This occurs when the connectivity of the ligands to the central metal ion is different. Different ligands can be present in the coordination sphere.
- **Stereo Isomerism**: This occurs when the spatial arrangement of the ligands around the central metal ion is different. It includes geometrical (cis/trans) and optical isomerism.

### Step 2: Identify Complexes
We need to examine the given complexes to determine which one shows both types of isomerism. The complexes mentioned in the transcript include:
1. **[Pt(en)2Cl2]**
2. **[Pt(NH3)ClBr]**

### Step 3: Analyze Each Complex
1. **[Pt(en)2Cl2]**:
- **Structural Isomerism**: This complex can show structural isomerism because it has two different types of ligands (ethylenediamine (en) and chloride (Cl)). The arrangement of these ligands can vary.
- **Stereo Isomerism**: This complex can also show stereo isomerism. It can exist in cis and trans forms due to the arrangement of the bidentate ligands (en) and the chloride ligands. Additionally, it can exhibit optical isomerism if it lacks a plane of symmetry.

2. **[Pt(NH3)ClBr]**:
- **Structural Isomerism**: This complex does not show structural isomerism because it contains the same types of ligands (NH3, Cl, Br) and does not have different connectivity.
- **Stereo Isomerism**: It can show geometrical isomerism (cis/trans) but does not exhibit optical isomerism due to the presence of a plane of symmetry.

### Step 4: Conclusion
Based on the analysis, **[Pt(en)2Cl2]** is the complex that shows both structural and stereo isomerism.

### Final Answer
The complex that shows both structural and stereo isomerism is **[Pt(en)2Cl2]**.

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