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Statement-1: In the reaction [CoCl(2)(NH...

Statement-1: In the reaction `[CoCl_(2)(NH_(3))_(4)]^(+)+Cl^(-) to [CoCl_(3)(NH_(3))_(3)]+NH_(3)`, when reactant is in cis-form two isomers of the product are obtained.
Statement-2: Third chloride ions replaces an ammonia cis to both chloride ion or trans to one of the chloride ion.

A

Statement-1 is True, Statement-2 is True , Statement-2 is a correct explanation for Statement-1.

B

Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1.

C

Statement-1 is True, Statement-2 is False.

D

Statement-1 is False, Statement-2 is True.

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The correct Answer is:
A
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[CoCl(NH_(3))_(5)]^(2+) is

[CoCl_(2)(NH_(3))_(4)]^(+)+Cl^(-) to [CoCl_(3)(NH_(3))_(3)]+NH_(3) . If in this reaction two isomers of the produt are obtained, which is true for the iniital (reactant) complex:

In the complex CoCl_(3).4NH_(3)

In the reaction [CoCI_(2)(NH_(3))_(4)]^(o+)rarr[CoCI_(3)(NH_(3))_(3)]+NH_(3) , only one isomer of the complex product is obtained Is the initial complex cis or trans ? .

Four statements for the following reaction given below [CoCl_(2)(NH_(3))_(4)]^(+) to [CoCl_(3)(NH_(3))_(3)]+NH_(3) (P) Only one isomer is produced if the ractant complex ion is a trans isomer (Q) Three isomers are produced if the reactant complex ion is a cis isomer (R ) Two isomers are produced if the reactant complex ion is trans isomer (S) Two isomers are produced if the reactant complex is cis isomer The correct statements are :

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