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The splitting diagram for square planar ...

The splitting diagram for square planar complexes is more complex than for octahedral and tetrahedral complexes and is shown below with the relative energies of each orbital.

Calculate crystal field stabilisation energy for a diamagnetic square planar `d^(8)` metal complex with the help of above diagram neglecting pairing energy (P)

A

`-2.88Delta_(0)`

B

`-2.44Delta_(0)`

C

`-1.65Delta_(0)`

D

`-4.84Delta_(0)`

Text Solution

Verified by Experts

The correct Answer is:
B
`d_(xz)^(2),d_(yz)^(2),d_(z^(2))^(2),d_(xy)^(2) =d^(8)`
CFSE`=4xx(-0.51Delta_(0))+2xx(-0.4Delta_(0))+2xx(0.23Delta_(0))`
`=-2.44Delta_(0)`
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The splitting diagram for square planar complexes is more complex than for octahedral and tetrahedral complexes and is shown below with the relative energies of each orbital. Which of the following set of de^(-) have same crystal field stabilisation energy value for tetrahedral complex neglecting pairing energy (P) : (P) d^(1), d^(6)" "(Q) d^(2), d^(7) (R ) d^(3), d^(8)" "(S) d^(4), d^(9) (T) d^(5), d^(10)

What is the crystal field stabilization energy for high spin d^6 octahedral complex?

Knowledge Check

  • Crystal field stabilization energy for high spin d^(4) octahedral complex is

    A
    `-0.6 Delta_(0)`
    B
    `-1.8 Delta_(0)`
    C
    `-1.6 Delta_(0) + P`
    D
    `-1.2 Delta_(0)`

  • Crystal field stablisation energy for high spin d^(4) octahedral complex is :-

    A
    `-1.8 Delta_(0)`
    B
    `-0.6 Delta_(0)`
    C
    `-1.2 Delta_(0)`
    D
    `-1.6 +P`

  • Crystal field stabilization energy for high spin d^4 octahedral complex is

    A
    `-0.6 triangle_circ`
    B
    `-1.8 triangle_circ`
    C
    -1.6 triangle_circ + p`
    D
    `-1.2 triangle_circ`

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