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Which of the following species given bel...

Which of the following species given below have shape similar to `XeOF_(4)`?

A

`XeO_(3)`

B

`IF_(5)`

C

`PCl_(5)`

D

`XeF_(5)^(o+)`

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AI Generated Solution

The correct Answer is:
To determine which species have a shape similar to `XeOF_(4)`, we first need to analyze the shape of `XeOF_(4)` itself. ### Step-by-Step Solution: 1. **Identify the Central Atom and Count Valence Electrons**: - The central atom in `XeOF_(4)` is Xenon (Xe). - Xenon has 8 valence electrons. The oxygen (O) contributes 6 valence electrons, and each fluorine (F) contributes 1 valence electron. - Total valence electrons = 8 (from Xe) + 6 (from O) + 4 (from 4 F) = 18 valence electrons. 2. **Calculate the Steric Number**: - The steric number is calculated as the number of bonded atoms plus the number of lone pairs on the central atom. - In `XeOF_(4)`, there are 4 fluorine atoms and 1 oxygen atom bonded to xenon, which gives us 5 bonded atoms. - Since xenon has 8 valence electrons and 5 are used for bonding, there are 3 electrons left, which means there is 1 lone pair. - Therefore, the steric number = 5 (bonded atoms) + 1 (lone pair) = 6. 3. **Determine the Geometry and Shape**: - A steric number of 6 indicates an octahedral geometry. - However, with one lone pair, the shape becomes square pyramidal. 4. **Analyze Other Species**: - We need to find species that also have a square pyramidal shape. We will calculate the steric number for each species. a. **IF5**: - Iodine (I) has 7 valence electrons, and 5 fluorine atoms contribute 5 electrons. - Total = 7 + 5 = 12 valence electrons. - Steric number = 5 (bonded) + 1 (lone pair) = 6. Shape = square pyramidal. b. **PCl5**: - Phosphorus (P) has 5 valence electrons, and 5 chlorine atoms contribute 5 electrons. - Total = 5 + 5 = 10 valence electrons. - Steric number = 5 (bonded) + 0 (lone pairs) = 5. Shape = trigonal bipyramidal (not similar). c. **XeF5+**: - Xenon has 8 valence electrons, and 5 fluorine atoms contribute 5 electrons. - Total = 8 + 5 = 13 valence electrons. - For the positive charge, we subtract 1 electron, so we have 12 electrons. - Steric number = 5 (bonded) + 1 (lone pair) = 6. Shape = square pyramidal. 5. **Conclusion**: - The species that have a shape similar to `XeOF_(4)` (square pyramidal) are **IF5** and **XeF5+**. ### Final Answer: The species that have a shape similar to `XeOF_(4)` are **IF5** and **XeF5+**.

To determine which species have a shape similar to `XeOF_(4)`, we first need to analyze the shape of `XeOF_(4)` itself. ### Step-by-Step Solution: 1. **Identify the Central Atom and Count Valence Electrons**: - The central atom in `XeOF_(4)` is Xenon (Xe). - Xenon has 8 valence electrons. The oxygen (O) contributes 6 valence electrons, and each fluorine (F) contributes 1 valence electron. - Total valence electrons = 8 (from Xe) + 6 (from O) + 4 (from 4 F) = 18 valence electrons. ...
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GRB PUBLICATION-CHEMICAL BONDING-I-STRAIGHT OBJECTIVE TYPE(B)
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  6. Which of the following has only sigma bonds?

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  8. If all the F atoms are replaced by 'O' atom from SF(4) without changin...

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  9. In XeO(3)F(2), d-orbital which is not used in bonding is :

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  10. A hybrid orbital formed from s and p-orbital can contribute to

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  11. Which of the following has sp^(3) hybridisation?

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  12. Which of the following is sp^(3) d hybridised as well as has trigonal ...

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  20. The ratio of sigma bond in P(4)O(10) and P(4)O(6) is respectively :

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