Which of the following compound has number of `p pi-p pi` bond is equal to number of `p pi-d pi` bond?

Options

A. `SO_(2)`
B. `CO_(2)`
C. `SO_(3)`
D. `SOCl_(2)`

Explanation

To determine which compound has the number of `p pi-p pi` bonds equal to the number of `p pi-d pi` bonds, we will analyze the given compounds one by one.

### Step 1: Analyze SO2
- **Valence Electrons**: Sulfur has 6 valence electrons, and each oxygen has 6 valence electrons (2 oxygen atoms contribute 12).
- **Total Valence Electrons**: 6 (S) + 12 (O) = 18 electrons.
- **Structure**: Sulfur forms two double bonds with two oxygen atoms.
- **Bond Types**:
- Each double bond consists of one sigma and one pi bond.
- The pi bonds are formed from the p orbitals of sulfur and oxygen.
- **Count of Bonds**:
- Total pi bonds = 2 (from two double bonds).
- `p pi-p pi` bonds = 2 (one from each double bond).
- `p pi-d pi` bonds = 0 (since sulfur does not use d orbitals in SO2).
- **Conclusion**: Not equal.

### Step 2: Analyze CO2
- **Valence Electrons**: Carbon has 4 valence electrons, and each oxygen has 6 valence electrons (2 oxygen atoms contribute 12).
- **Total Valence Electrons**: 4 (C) + 12 (O) = 16 electrons.
- **Structure**: Carbon forms two double bonds with two oxygen atoms.
- **Bond Types**:
- Each double bond consists of one sigma and one pi bond.
- **Count of Bonds**:
- Total pi bonds = 2 (from two double bonds).
- `p pi-p pi` bonds = 2 (one from each double bond).
- `p pi-d pi` bonds = 0 (no d orbital involvement).
- **Conclusion**: Not equal.

### Step 3: Analyze SO3
- **Valence Electrons**: Sulfur has 6 valence electrons, and each oxygen has 6 valence electrons (3 oxygen atoms contribute 18).
- **Total Valence Electrons**: 6 (S) + 18 (O) = 24 electrons.
- **Structure**: Sulfur forms three double bonds with three oxygen atoms.
- **Bond Types**:
- Each double bond consists of one sigma and one pi bond.
- **Count of Bonds**:
- Total pi bonds = 3 (from three double bonds).
- `p pi-p pi` bonds = 3 (one from each double bond).
- `p pi-d pi` bonds = 0 (no d orbital involvement).
- **Conclusion**: Not equal.

### Step 4: Analyze SOCl2
- **Valence Electrons**: Sulfur has 6 valence electrons, oxygen has 6, and chlorine has 7 (2 chlorine atoms contribute 14).
- **Total Valence Electrons**: 6 (S) + 6 (O) + 14 (Cl) = 26 electrons.
- **Structure**: Sulfur forms one double bond with oxygen and two single bonds with chlorine.
- **Bond Types**:
- The double bond with oxygen consists of one sigma and one pi bond.
- **Count of Bonds**:
- Total pi bonds = 1 (from the double bond).
- `p pi-p pi` bonds = 1 (from the double bond).
- `p pi-d pi` bonds = 0 (no d orbital involvement).
- **Conclusion**: Not equal.

### Final Conclusion
None of the compounds analyzed have the number of `p pi-p pi` bonds equal to the number of `p pi-d pi` bonds.