The geometry of `H_(2)S` and its dipole moment are :

Options

A. angular and non zero
B. angular and zero
C. linear and non zero
D. linear and zero

Explanation

To determine the geometry and dipole moment of \( H_2S \), we can follow these steps:

### Step 1: Identify the Central Atom
In \( H_2S \), sulfur (S) is the central atom because it is less electronegative than hydrogen (H) and can form two bonds with hydrogen.

**Hint:** The central atom in a molecule is usually the least electronegative element that can form multiple bonds.

### Step 2: Determine the Valence Electrons
Sulfur is in group 16 of the periodic table and has 6 valence electrons. Each hydrogen atom contributes 1 electron, giving a total of 2 electrons from the two hydrogens. Thus, the total number of valence electrons in \( H_2S \) is \( 6 + 2 = 8 \) electrons.

**Hint:** Count the valence electrons of each atom to find the total number of electrons available for bonding.

### Step 3: Draw the Lewis Structure
In the Lewis structure of \( H_2S \), sulfur is bonded to two hydrogen atoms with single bonds. Sulfur also has two lone pairs of electrons. The structure can be represented as:

```
H
|
H--S
|
(Lone Pair) (Lone Pair)
```

**Hint:** Use dots to represent lone pairs and lines to represent bonds in the Lewis structure.

### Step 4: Determine the Molecular Geometry
The presence of two lone pairs and two bonding pairs around the sulfur atom leads to a bent or angular geometry according to the VSEPR theory. The bond angle is approximately 104.5°.

**Hint:** Use VSEPR theory to predict the shape based on the number of bonding and lone pairs.

### Step 5: Analyze the Dipole Moment
In \( H_2S \), sulfur is more electronegative than hydrogen, which means that the S-H bonds will have a dipole moment directed towards sulfur. Additionally, the two lone pairs on sulfur contribute to the overall dipole moment.

- The dipole moments from the S-H bonds do not cancel out due to the bent shape of the molecule. Instead, they add up to produce a net dipole moment that is directed upwards.

**Hint:** Consider the direction of the dipole moments based on electronegativity and the geometry of the molecule.

### Step 6: Conclusion
The geometry of \( H_2S \) is angular (or bent), and it has a non-zero dipole moment directed upwards.

**Final Answer:** The geometry of \( H_2S \) is angular, and its dipole moment is non-zero.